How to Find Extrema, Roots, Inflection Points, and Concavity Using Derivatives?

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Homework Statement



y=3(x-1)^{\frac{1}{3}}-(x-1)^{2}

I need to find all extrema, roots, inflection points, and concavity using first and second derivative tests.
I usually do not have a problem with these, but I need to find some extrema that I know exist.

The Attempt at a Solution



y'=2(x-1)^{\frac{-1}{3}}-2(x-1)

simplified to:

y'=\frac{2+(-2x+2)(x-1)^{\frac{1}{3}}}{(x-1)^{\frac{1}{3}}}

From looking at a graph I can see that there are extrema at x=0, and x=2. There is also a sharp turn at (1,0). However, i am not seeing these extrema in my first derivative. Did I not simplify enough or make an algebraic error?
 
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crybllrd said:

Homework Statement



y=3(x-1)^{\frac{1}{3}}-(x-1)^{2}

I need to find all extrema, roots, inflection points, and concavity using first and second derivative tests.
I usually do not have a problem with these, but I need to find some extrema that I know exist.

The Attempt at a Solution



y'=2(x-1)^{\frac{-1}{3}}-2(x-1)
There's a mistake in the above.
d/dx(3(x - 1)^(1/3)) = (x - 1)^(-2/3)
crybllrd said:
simplified to:

y'=\frac{2+(-2x+2)(x-1)^{\frac{1}{3}}}{(x-1)^{\frac{1}{3}}}

From looking at a graph I can see that there are extrema at x=0, and x=2. There is also a sharp turn at (1,0). However, i am not seeing these extrema in my first derivative. Did I not simplify enough or make an algebraic error?
 
Thanks, I'm not sure how I missed that. I can take it from here.
Thanks again
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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