How to Find h in Hydrostatics?

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To find the height h in hydrostatics, the problem can be approached using the hydrostatic pressure relation and the given parameters: H1, H2, specific gravity of mercury (SG)Hg, liquid density (gammaL), and atmospheric pressure (patm). The confusion arises from the use of heights instead of depths, which complicates the calculation. The relationship to balance excess pressures involves the equation H2 - (H1 - h)γHg = hγL. The corrected equation should be [H2 - (H1 - h)]γHg = hγL. This approach will help in determining the value of h accurately.
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Homework Statement



So this is a five part problem. I have already done the first 4 parts that involved the mess of different liquids to the left in the diagram.

I am only concerned with finding h now, which I believe does not even require me to look at the left hand side of the diagram.

I should be able to find it using only H1, H2, (SG)Hg, gammaL and patm

I also labeled a point a because I believe it will be of use to me.

Picture1-33.png

Homework Equations



The hydrostatic relation p=p_o+\rho g y=p_o+\gamma yCan someone give me a hint? I have done tons of these before, but I am stumped for some reason on this one :redface:

What is confusing is that i am given "heights" and not "depths." Not sure why that is effing me up so badly.
 
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Hg level in left tube = H1 - h
Hg level in right tube = H2
Find the excess mercury level in the right hand tube.
Excess pressure due to this level must be balanced by the excess pressure due to h level of liquid of density of γL.
 
H2-(H1-h)γHg=hγL

That look about right rl.bhat ?
 
Saladsamurai said:
H2-(H1-h)γHg=hγL

That look about right rl.bhat ?

It should be [H2-(H1-h)]γHg=hγL
 

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