How to find the angle between F2 and the x axis?

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To find the angle between force F2 and the x-axis, the cosine rule can be applied using the known angle of F1 with the negative x-axis, which is 70 degrees. This implies that the angle with the positive y-axis is 20 degrees. However, the user struggles to derive the resultant force and is uncertain about the completeness of the information provided. The discussion highlights the need for additional details to accurately determine the angle and resultant force. Without further data, the angle of F2 remains indeterminate.
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Homework Statement


Find the angle between the x-axis and the force F2, and the magnitude of the resultant force?


Homework Equations


The equation of the triangle:
a(squared) = b(squared) + c(squared) - 2bc cos A


The Attempt at a Solution


What I did was that I said that since the angle between the f1 and the negative x-axis is 70 degrees. Then the angle with the +y axis should be 20 degrees, and therefore if we make the whole two forces as a triangle and solve using the cosine rule, we should get the value of the resultant force, but after wasting countless amounts of paper, I still haven't got a solution? Any help will be greatly appreciated!
 

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Was there any other information that you have left out? The angle could be anything without extra information.
 
Nope that is all the information given!
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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