How to Find the Cartesian Equation for a Plane Parallel to the x-axis?

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To find the Cartesian equation for a plane parallel to the x-axis and passing through the points (1,2,1) and (2,1,4), the direction vector derived from these points is (1,-1,3). The normal vector to the plane, denoted as N, must be perpendicular to any vector in the plane, including the vector (1, 0, 0) since the plane is parallel to the x-axis. Consequently, the equation of the plane can be expressed without an x component, leading to the form Ay + Bz = D. By substituting the coordinates of the two points into this equation, two equations can be established to solve for the coefficients A and B. The solution will yield the desired Cartesian equation of the plane.
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Homework Statement



Determine the Cartesian equation for the plane with the following:
1) through the points (1,2,1) and (2,1,4)
2) parallel to x-axis

Homework Equations


Parametric Equations
Vector Eqs
Plane Eqs


The Attempt at a Solution


I basically understand how perpendicular works, but not sure how parallel will change this situation. I know that I will get a direction vector out of this from the first two points, which will be (1,-1,3), but then I don't know what to do after..
 
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OK, you have so far that D = <1,-1,3> is in the plane, so it is perpendicular to the plane's normal, call it N. If (x,y,z) is a variable point in the plane you can make another vector in the plane and perpendicular to the plane's normal N.

So the problem boils down to what does the normal vector N to the plane look like if the plane is parallel to the x axis? What can you say about its components?
 
If a plane is parallel to the x-axis, then the vector \vec{i}, or (1, 0, 0) in your notation, is in the plane. Use the two given points to find another vector in the plane and take their cross product to get a vector normal to the plane.

Another way to look at it is this: if the plane is parallel to the x-axis, there will be NO x in the formula. Write Ay+ Bz= 1 and use the two points to get two equations to solve for A and B.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...

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