Domnu
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Problem
Consider an operator \hat{A} whose commutator with the Hamiltonian \hat{H} is the constant c... ie [\hat{H}, \hat{A}] = c. Find \langle A \rangle at t > 0, given that the system is in a normalized eigenstate of \hat{A} at t=0,corresponding to the eigenvalue a.<br /> <br /> <b>Attempt Solution</b><br /> We know that<br /> <br /> \frac{\partial \langle A \rangle}{dt} = \langle \frac{i}{\hbar} [\hat{H}, \hat{A}] + \frac{\partial \hat{A}}{\partial t} \rangle = \langle \frac{i c}{\hbar} + 0 \rangle = \frac{i c}{\hbar}.<br /> <br /> Is this correct? (I&#039;m just confirming that d\hat{A}/dt = 0 since we&#039;re in an eigenstate of \hat{A}). But this means that the expected value of A is complex... clearly, \hat{A} is not Hermitian then, right?
Consider an operator \hat{A} whose commutator with the Hamiltonian \hat{H} is the constant c... ie [\hat{H}, \hat{A}] = c. Find \langle A \rangle at t > 0, given that the system is in a normalized eigenstate of \hat{A} at t=0,corresponding to the eigenvalue a.<br /> <br /> <b>Attempt Solution</b><br /> We know that<br /> <br /> \frac{\partial \langle A \rangle}{dt} = \langle \frac{i}{\hbar} [\hat{H}, \hat{A}] + \frac{\partial \hat{A}}{\partial t} \rangle = \langle \frac{i c}{\hbar} + 0 \rangle = \frac{i c}{\hbar}.<br /> <br /> Is this correct? (I&#039;m just confirming that d\hat{A}/dt = 0 since we&#039;re in an eigenstate of \hat{A}). But this means that the expected value of A is complex... clearly, \hat{A} is not Hermitian then, right?