How to find the potential difference with constant charge

AI Thread Summary
To find the electric field and potential difference in a capacitor with constant charge density, one can use Gauss's law, represented by the equation int E dot dA = Qencl/epsilon0. The potential difference can then be calculated using the integral V ab = int E dot dl. The challenge arises in adapting these equations for a medium with constant charge density, as the approach differs from scenarios involving a vacuum or dielectric. Understanding the distribution of the electric field in the presence of charge density is crucial for solving the problem. Clarifying these concepts will aid in determining the electric field and potential difference effectively.
mattz205
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Homework Statement


How would i go about finding the electric field and potential difference when there is a constant charge density between the capacitor rather than a vacuum?

Homework Equations


int E dot dA = Qencl/epsilon0
V ab = int E dot dl

The Attempt at a Solution


to be honest I am not really sure where to start this, i know how to find all this when there is a vacuum or dielectric, but what would i do to find it when there is a constant charge density?
 
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mattz205 said:

Homework Statement


How would i go about finding the electric field and potential difference when there is a constant charge density between the capacitor rather than a vacuum?

Homework Equations


int E dot dA = Qencl/epsilon0
V ab = int E dot dl

The Attempt at a Solution


to be honest I am not really sure where to start this, i know how to find all this when there is a vacuum or dielectric, but what would i do to find it when there is a constant charge density?
Please post the problem as stated to you.
 

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