How to handle string intersection in static friction calculation?

AI Thread Summary
The discussion focuses on calculating the minimum coefficient of static friction required for a system in equilibrium involving two masses and ideal strings. The equations of motion for both the larger mass and the smaller mass are set up, with tension (T) being a critical variable. The user questions the treatment of string intersections and the application of trigonometric functions in the equations. After resolving the equations, the relationship between the coefficient of static friction (μ) and the angles involved leads to the conclusion that μ equals tan(30)/3. The calculations confirm the correct approach to finding μ in the context of static friction and equilibrium.
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Homework Statement



a mass m is supported as shown in the figure by ideal strings connected to a rigid wall and to tal mass 3m sitting on a horizontal surface. what is the minimum coefficient of static friction between the larger mass and the surface that permits the system to remain in equilibrium in the situation shown

Homework Equations





The Attempt at a Solution



Big block

Fx = u3mg - T = 0

Little block & strongs

Fx = T - mgsin60 = 0

T = us3mg - mgsin60


I don't think this is correct. How do u deal with the string intersection
 

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For big block Fx = μ*3mg - T*sin30 = 0
For smaller block Fy = ...?
 
Why is the tension have the sin 30 doesn't the tension come directly in the x plain

so is Fy = mg - Tcos30 = 0
 
Correct.
Eliminate T and find the value of μ.
 
u3mg -Tsin30 = 0
mg - t cos30 = 0 t = mg/cos30
u3mg - mgsin30(cos30) = 0
u = tan30/3
 
Correct.
 
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