How to Integrate 6t(4+t^2)^.5 dt using u-substitution?

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The integration of the expression 6t(4+t^2)^(0.5) dt can be effectively solved using u-substitution. By letting u = 4 + t^2, the differential du is calculated as 2t dt, leading to dt = du/(2t). The integral simplifies to 3u^(0.5) du, which results in 2(4 + t^2)^(1.5) upon integration. This method confirms that the final answer is indeed 2(4 + t^2)^(3/2).

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Homework Statement



6t(4+t^2)^.5 dt




The Attempt at a Solution



I know the answer...what are the steps of how to get there
2(4+t^2)^3/2
 
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rjs123 said:

Homework Statement



6t(4+t^2)^.5 dt

The Attempt at a Solution



I know the answer...what are the steps of how to get there
2(4+t^2)^3/2
Do you know how integration by substitution is done? If not, look it up in your book.
Try a u-substitution. That is let u=4+t^2. Where do you go from here?
 
sutupidmath said:
Do you know how integration by substitution is done? If not, look it up in your book.
Try a u-substitution. That is let u=4+t^2. Where do you go from here?

du = 2t dt

dt = du/2t

3[u^.5 * du]

3(u^1.5)/1.5

2 (4 + t^2)^1.5

is this how it should be done?
 
Last edited:

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