How to know the caracteristics of this graph

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i need to determine wether its linear or non linear,time variant or time invariant,bilateral,
voltage controlled
current controlled
passive or active.

the graph is
v+10i=0

which one of them could be said
about this graph
?
 
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You must have some kind of idea about whether that voltage vs current graph has any of those properties. Tell us what you know. If you don't know what they mean, you had better look it up.
 
i have this kind of resistor.
v=(cos2t)i+3

i don't know to to draw its grapg

because there are 3 variables
and i don't know why its currect contolled
and not voltage controlled too
..
 
electron2 said:
i have this kind of resistor.
v=(cos2t)i+3

i don't know to to draw its grapg

because there are 3 variables
and i don't know why its currect contolled
and not voltage controlled too
..

When you have three variables the only way to really draw a graph is to hold one fixed and graph the relation between the other two. In this case I'd graph v versus t at fixed i, and v versus i at fixed t. To see why you would regard it as current controlled think about what a graph of i versus t and fixed v would look like. It's much easier to describe the behavior of the system as a function of time at fixed i than it is at fixed v.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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