How to prove the following identity

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Homework Statement



e_j=g_(jk)e^k

where e_j is a covariant vector base
e^k is a a contravariant vector base
g_(jk) is the covariant metric

Homework Equations





The Attempt at a Solution

 
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What is the definition of the "covariant metric". How do you go from a covariant to the corresponding contravariant vector and vice-versa?
 
Hi, by saying "covariant metic" I mean writing the metric in its covariant form - basically g(contra)=[g(cov)]^(-1)
you can use the metric to lower/raise an index on a vector component but here e_j and e^k are not components but the actual unit vectors.
 
Hi, by saying "covariant metic" I mean writing the metric in its covariant form - basically g(contra)=[g(cov)]^(-1)
you can use the metric to lower/raise an index on a vector component but here e_j and e^k are not components but the actual unit vectors.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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