- #1

aisha

- 584

- 0

[tex] y= -2sin [ 2\pi * \frac {(t+1)} {3} ] [/tex]

I need to state the period, amplitude, max/min, range, domain, horizontal phase shift, and vertical displacement

Im not sure how to rearrange the square brackets.

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- Thread starter aisha
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- #1

aisha

- 584

- 0

[tex] y= -2sin [ 2\pi * \frac {(t+1)} {3} ] [/tex]

I need to state the period, amplitude, max/min, range, domain, horizontal phase shift, and vertical displacement

Im not sure how to rearrange the square brackets.

- #2

Jameson

Gold Member

MHB

- 4,538

- 13

I would distribute the [tex]2\pi[/tex] and then separate the terms into the form of [tex]-2\sin{(At + B)}[/tex]. A and B will both be fractions, but setting it up in that way will allow you to more easily find all of the things you are looking for.

EDIT: The below method could be easier for you.

EDIT: The below method could be easier for you.

Last edited by a moderator:

- #3

Fermat

Homework Helper

- 872

- 1

rearrange it like this.aisha said:

[tex] y= -2sin [ 2\pi * \frac {(t+1)} {3} ] [/tex]

I need to state the period, amplitude, max/min, range, domain, horizontal phase shift, and vertical displacement

Im not sure how to rearrange the square brackets.

[tex] y= -2sin [ \frac{2\pi}{3} *(t+1) ] [/tex]

If you're still stuck, http://www.jmp.com/news/jmpercable/07_fall2000/regression.html for some help

- #4

Brad Barker

- 429

- 0

y = a sin(bx - c) + d

what do each of these letters (a, b, c, and d) do?

what are the values of a, b, c, and d for the function you wrote down? you may need to do some distributing to get into this general form.

- #5

aisha

- 584

- 0

Thanks so much that is a BIG HUGE HELP :rofl:

- #6

aisha

- 584

- 0

period=3

amplitude=0

max=2

min=-2

range{y:-2<=y<=2}

domain {x:XER}

horizontal phase shift 1 unit left

no vertical shift

Are these values correct? Should period have a unit with it or is just 3 fine? What about the amplitude is 0 amplitude possible?

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