How to Show u(x,y) and v(x,y) are Constant Throughout D?

tylerc1991
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Homework Statement



Suppose v is a harmonic conjugate of u in a domain D, and that u is a harmonic conjugate of v in D. Show how it follows that u(x,y) and v(x,y) are constant throughout D.

The Attempt at a Solution



since u is a harmonic conjugate of v, u_xx + u_yy = 0
also, since v is a harmonic conjugate of u, v_xx + v_yy = 0

u_x = v_y => u_xx = v_yx
u_y = -v_x => u_yy = -v_xy

I think that I am going in circles here. Can someone lend a helping hand with this problem? Thank you so much!
 
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Hint: in one direction u_x=v_y and u_y=(-v_x). In the other direction v_x=u_y and v_y=(-u_x). Put them together.
 
what do you mean in one direction?

do you mean that since u is a harmonic conjugate then that is one direction, and since v is a harmonic conjugate then that is the other direction?
 
tylerc1991 said:
what do you mean in one direction?

do you mean that since u is a harmonic conjugate then that is one direction, and since v is a harmonic conjugate then that is the other direction?

Yes, that's exactly what I mean.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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