Dell
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4\int9\frac{1-\sqrt{x}}{\sqrt{x}+2}
what i did:
t=\sqrt{x}
x=t2
dx=x'dt=2tdt
now my integration is from 2-3 instead of 4-9
\int\frac{1-t}{t+2}2tdt=2\int\frac{t-t<sup>2</sup>}{t+2}dt
=2(\int\frac{t}{t+2}dt-\int\frac{t<sup>2</sup>}{t+2}dt)
the 1st integral i can replace with\int1-\frac{2}{t+2}dt which is an immediate integral, but how do i simplify the second part??
what i did:
t=\sqrt{x}
x=t2
dx=x'dt=2tdt
now my integration is from 2-3 instead of 4-9
\int\frac{1-t}{t+2}2tdt=2\int\frac{t-t<sup>2</sup>}{t+2}dt
=2(\int\frac{t}{t+2}dt-\int\frac{t<sup>2</sup>}{t+2}dt)
the 1st integral i can replace with\int1-\frac{2}{t+2}dt which is an immediate integral, but how do i simplify the second part??