How to solve a hard question involving multiplication of ln(t) and sin(t)

AI Thread Summary
The equation 3 = ln(t) * sin(t) cannot be solved algebraically due to the transcendental nature of the functions involved, but approximate solutions can be found using a graphing calculator, with the smallest value for t being around 20.3. For the derivative of y = ln(t) * sin(t), the correct application of the product rule yields dy/dx = ln(t) * cos(t) + sin(t)/t. Similar to the first equation, dy/dx = 0 does not have an algebraic solution, but an approximate value of x is around 0.35. The discussion highlights the challenges of solving transcendental equations and the utility of numerical methods for finding solutions.
dagg3r
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hi guys,
this is a question i got really confused on

they give you a question which is 3=ln(t) * sin(t)

solve for t. i don't know how to do this algebracially if it is even possible. i can do it on my calculator by sketching the graph and finding the exact value but how do you do this algebracially?.

The best i can get is ln(t) = 3/sin(t) but still i can't solve lol.



2. find the derivative of y=ln(t) * sin(t) i used the product rule and got
U=ln(x)
u`=1/x
V=sin(x)
v`=cos x
Dy/dx= ln(x)* cos(x) + sin(x)/x
if i let dy/dx=0 how do i solve for x?
 
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ln(t) and sin(t) are both "transcendental" functions and, in general, there is no algebraic way to get an exact value. You can, as you say, use a graphing calculator to get an approximate (not exact) value for t. The equation 3= ln(t)*sin(t) has an infinite number of solutions but I get approximately x= 20.3 for the smallest.

As for problem 2, yes, dy/dx= ln(x)* cos(x) + sin(x)/x. Again, there is no algebraic way to get an exact solution to dy/dx= 0. You could again get an approximate solution using a graphing calculator. Once again, there are an infinite number of solutions and I find the smallest to be about x= 0.35.
By the way, why do you want to solve that equation? The problem as you stated it only asked you to find the derivative and you have done that.
 
ok, thanks but there is another question that says algebracially is that the same as this?

y=0.5e^(0.1x)sin(t)
 
perhaps Euler's famous equation may be of some service?
 
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