How to solve an Improper Integral of Type 2?

cmab
Messages
32
Reaction score
0
I've posted on Homeworks one of the number I did not understand. However, I would like to know the steps to calculate an improper integral of type 2. The type 2 is the one from constant a to constat b, not the one with inifnite.

Please tell me the steps the accomplish it. :smile:

I know that I'm supposed to set the limits, then put it in the integral form, than FTC it. But, I'm not sure.
 
Physics news on Phys.org
Could you give example so I could understand question a little better.
 
limitapproaches0 said:
Could you give example so I could understand question a little better.


Let's say something like [int a=0 b=2] 1/(x-1)^(1/3) dx
 
Use the theorem of addition

\int_{0}^{2} f(x) \ dx=\int_{0}^{1} f(x) \ dx+\int_{1}^{2} f(x) \ dx

You have to integrate & compute 2 limits...

Daniel.
 
dextercioby said:
Use the theorem of addition

\int_{0}^{2} f(x) \ dx=\int_{0}^{1} f(x) \ dx+\int_{1}^{2} f(x) \ dx

You have to integrate & compute 2 limits...

Daniel.

The limits would be 1+ and 1- right ?
 
It should be

\lim_{a\nearrow 1}\int_{1}^{a} f(x) \ dx

\lim_{b\searrow 1}\int_{b}^{2} f(x) \ dx


Daniel.
 
Back
Top