How to Solve an Improper Integral Problem

learningsumth
Messages
3
Reaction score
0

Homework Statement


hi, I've been working on this for the past half hour and i can't seem to get the right answer

definite integral from 1 to infinity, dx/[(x)(2x+5)]
[PLAIN]http://www3.wolframalpha.com/Calculate/MSP/MSP558719f9237h7g3ceg5000000h4efg42afe11g4c?MSPStoreType=image/gif&s=27&w=272&h=39

The Attempt at a Solution



i keep getting (2/5)ln(7) as opposed to (1/5)log(7/2) that wolfram gives me.

thanks so much!
 
Last edited by a moderator:
Physics news on Phys.org
It's difficult to see what your mistake is if you don't show us your work.
 
learningsumth said:

Homework Statement


hi, I've been working on this for the past half hour and i can't seem to get the right answer

definite integral from 1 to infinity, dx/[(x)(2x+5)]
[PLAIN]http://www3.wolframalpha.com/Calculate/MSP/MSP558719f9237h7g3ceg5000000h4efg42afe11g4c?MSPStoreType=image/gif&s=27&w=272&h=39


The Attempt at a Solution



i keep getting (2/5)ln(7) as opposed to (1/5)log(7/2) that wolfram gives me.

thanks so much!

LCKurtz - can you show some work so we might be able to find where you went wrong? For example, how did you perform integration?
 
Last edited by a moderator:
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Replies
6
Views
2K
Replies
10
Views
2K
Replies
2
Views
1K
Replies
3
Views
2K
Replies
1
Views
2K
Replies
4
Views
5K
Replies
14
Views
3K
Replies
21
Views
4K
Back
Top