How to Solve for atan when an object turns 60 degrees

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To compute the tangential acceleration (atan) of a flywheel after it has turned 60 degrees, the formula atan = α * radius is used, where α is the angular acceleration. Given that the flywheel has a radius of 0.200 meters and an angular acceleration of 0.900 rad/s², the tangential acceleration remains constant at 0.180 m/s², regardless of the angle turned. The initial confusion about needing to account for the distance moved was resolved, confirming that atan is solely dependent on the angular acceleration and radius. Thus, the tangential acceleration at 60 degrees is 0.180 m/s².
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Homework Statement

A flywheel with a radius of 0.200 starts from rest and accelerates with a constant angular acceleration of 0.900 .

atan= .180 m/s2 when its at rest
arad= 0m/s2 when at rest
compute magnitude of resultant acceleration at the start a= .180 m/s2

I got all of these already now the question is

Compute the magnitude of the tangential acceleration of a point on its rim after it has turned through 60.0?

atan= ? m/s2

The attempt at a solution

I do not know how to answer this. I honeslty don't know where to start.

I know atan= \alpha*radius but i don't know what to do now that the flywheel is turning 60
 
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Solved it.

Turned out that i didnt need to worry about how far it moved so it was just Alpha*radius

Giving me atan=.180m/s^2
 
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