- #1

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cot^a(x) csc^b(x) dx

If a and b are odd?

An explanation of the strategy would be a huge help!

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- Thread starter adelaide87
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- #1

- 24

- 0

cot^a(x) csc^b(x) dx

If a and b are odd?

An explanation of the strategy would be a huge help!

- #2

- 83

- 0

cot^a(x) = Cos^a(x) / sin^a(x)

csc^b(x) = 1/sin^b(x)

this is where i would start. from there, you can sum the powers of the sin's in the denominators and try u substitution or something.

- #3

Mark44

Mentor

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Take out one factor each of csc x and cot x, leaving you with

cot^a(x) csc^b(x) dx

If a and b are odd?

An explanation of the strategy would be a huge help!

[tex]\int cot^{a-1}(x)csc^{b - 1}(x)~csc(x)cot(x)dx[/tex]

Use the identity cot

At that point you'll have a sum of terms that involve various powers of csc

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