How would one connect three 9Ω resistors to get 12Ω?

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Discussion Overview

The discussion revolves around the question of how to connect three 9Ω resistors to achieve a total resistance of 12Ω. Participants explore various configurations, including series and parallel connections, and express uncertainty about the solution.

Discussion Character

  • Exploratory, Debate/contested, Homework-related

Main Points Raised

  • One participant suggests that the relevant equations involve series and parallel resistance connections.
  • Another participant hints that cutting the resistors in half may be necessary to achieve the desired resistance.
  • A different participant claims they can achieve the resistance with four resistors, questioning the original problem's interpretation.
  • Another participant expresses a preference for a specific answer without elaborating on the reasoning.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on how to connect the resistors, with multiple competing views and interpretations of the problem remaining unresolved.

Contextual Notes

There is uncertainty regarding the methods to connect the resistors, and assumptions about the problem's requirements may not be fully articulated.

bpani
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how would one connect three 9Ω resistors to get 12Ω??

Statement
-----------
how would one connect three 9Ω resistors to get 12Ω??

equations
-----------
i guess the relevant equations would be nothing more than series & parallel resistance connections..


The attempt at a solution
-------------------------
I've tried all possible ways to connect them (only 4 diff ways I guess??). There is apparently a solution since its in my nephew's textbook.
 
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bpani said:
Statement
-----------
how would one connect three 9Ω resistors to get 12Ω??

equations
-----------
i guess the relevant equations would be nothing more than series & parallel resistance connections..


The attempt at a solution
-------------------------
I've tried all possible ways to connect them (only 4 diff ways I guess??). There is apparently a solution since its in my nephew's textbook.

Hint -- you are going to have to cut the resistors in half with a fine saw...
 


I can do it with 4. Are you sure you read the problem correctly?
 


But I like Berkeman's answer better.
 

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