Hybridization of S & F: Atomic Orbitals & Electrons

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Sulfur (S) has available bonding orbitals consisting of one s and one p orbital, while fluorine (F) has one p orbital for bonding due to its position in group 17. The number of electrons in an orbital formed from overlapping different atomic orbitals can vary based on the specific orbitals involved. The discussion also mentions the compound SF6, which requires the consideration of d orbitals and involves sp3d2 hybridization. The complexities of quantum mechanics and hybridization in bonding are acknowledged as challenging concepts.
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Homework Statement


1. What atomic orbital/orbitals are available for bonding for S (Sulfur) and F (Fluorine)?
2. How many electrons are in an orbital formed from the overlapping of two atomic orbitals, which are different?

Homework Equations


N/A


The Attempt at a Solution


1. For this question, I inferred that only one P orbital was available for bonding in Fluroine, since it is in group 17 and whatnot. As for Sulfur, I'm guessing that 1 s and 1 p orbital would only be available; but then again, this question is quite confusing.

2. For this question, don't the answers vary? Doesn't it depend on what two atomic orbitals your overlapping with?

Sorry, I know these questions are a bit confusing; the whole quantum idea is crazy! :S
 
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What compound are you looking at?

The compound that comes to mind is that of SF6 in which you will need to invoke d orbitals as well. That would be the so called "sp3d2" hybridization; but don't tell a quantum field theorist...
 
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