Hybridized orbitals (can't understand diagram)

  • Thread starter Thread starter coconut62
  • Start date Start date
  • Tags Tags
    Diagram Orbitals
AI Thread Summary
Boron has an electronic configuration of 1s² 2s² 2p¹, but it possesses three 2p orbitals, which include one occupied and two unoccupied. The notation [He] indicates the electron configuration of helium, allowing for a more concise representation of boron's configuration as [He] 2s² 2p¹. This shorthand is useful for larger atoms to avoid lengthy configurations that can lead to errors. Hybridization involves the 2s and two of the 2p orbitals, while the 1s orbital remains closed and does not participate due to a significant energy gap. All subshells exist in theory, but only the relevant orbitals are considered during hybridization discussions.
coconut62
Messages
161
Reaction score
1
Please see attachment.

1. "Now the 2s orbital and two of the 2p orbitals of B hybridize to form a set of three equivalent sp2 hybrid orbitals." The notes says.

Can someone tell me why are there two 2p orbitals in B? I thought electronic configuration of B is 1s2 2s2 2p1?

2. What does the [He] beside B mean?

Thanks in advance.
 

Attachments

  • Chem.jpg
    Chem.jpg
    27.6 KB · Views: 410
Chemistry news on Phys.org
coconut62 said:
Can someone tell me why are there two 2p orbitals in B? I thought electronic configuration of B is 1s2 2s2 2p1?

Orbitas - as a place for an electron - exist regardless of whether they are occupied or not.

What does the [He] beside B mean?

It is a shortcut notation - replace [He] with configuration of the noble gas.
 
Why is Helium needed? Is it the Boron itself hybridizes or it hybridizes together with He?
 
coconut62 said:
Why is Helium needed? Is it the Boron itself hybridizes or it hybridizes together with He?

Helium is not needed, the notation simply means the electronic configuration of He.

So, instead of 1s2 2s2 2p1; as He is 1s2 you can write it as [He] 2s2 2p1. May not be so much of an advantage here, but in larger atoms like e.g. Gold, or Iodine having to write out lots of terms each time is prone to error.
 
Think about cesium. [Xe] 6s1 looks much more neat than 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s1, doesn't it? And they mean exactly the same.
 
So the [He] is actually together with the dotted square, not the B on the left?

And is the energy level of the hybrid orbitals lower than the 2p's? And higher than the 2s?
 
coconut62 said:
So the [He] is actually together with the dotted square, not the B on the left?

You can put it that way.
 
How about its energy level?
 
B has three 2p orbitals. And one 2s.
Empty orbital doesn't hybridize.
 
  • #10
ycheff said:
B has three 2p orbitals. And one 2s.
Empty orbital doesn't hybridize.

Where is its 1s?
 
  • #11
1s2 - (or [He]) - closed shell.
It can't hybridize. Too much energy gap between 1s and 2s.
 
  • #12
So you're saying that a B atom never has a 1s subshell? Even when it is an independent atom and not bonded to others?
 
  • #13
No, he says that 1s2 exists, but doesn't matter when talking about hybrydization and can be safely ignored. But I agree that the original statement was lousy to say the least.
 
  • #14
How come boron has so many subshells when it has only five electrons?

1s2 2s2 2p1 no?

is the 1s2 empty?
 
  • #15
Technically all possible subshells always exist, they are just not occupied in the unexcited atom.
 
Back
Top