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Hydrate and NaOH reaction

  1. Nov 6, 2006 #1
    I'm trying to figure out how to go about writing the net ionic equation for :

    [tex]Cu(NH_{4})_{2}(SO_{4})_{2} x 6H_{2}O + NaOH [/tex]

    incase that doesn't show, Cu(NH4)2(SO4)2 x 6H2O + NaOH... (thats a hydrate there)
    I believe a precipitate is suppose to form, but i have no clue how to go about this one where it has 3 ions in it, Cu, NH4, and SO4.... help is much appreciated!

    Thanks,
    Chris
     
    Last edited: Nov 6, 2006
  2. jcsd
  3. Nov 6, 2006 #2
    What are the cations? What are the anions? Break the equation up into them, and you should see your answer.
     
  4. Nov 6, 2006 #3
    hmm, ok, i think this is correct then?

    Cu2+ 2NH4+ 2SO42- 6H+ 6OH- + Na+ OH-

    not sure what ones form the products here tho...
    thanks for the response!
     
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