Hydroelectric Power: Equations & Calculations

  • Thread starter Thread starter Etak
  • Start date Start date
  • Tags Tags
    Power
AI Thread Summary
Hydroelectric power generation relies on the energy of moving water, which includes gravitational potential energy (m*g*h) and kinetic energy (1/2mv^2). To calculate the power generated, it's essential to determine these energy values before and after the water passes through the power station. The difference in energy values indicates the energy transfer occurring within the station. This calculation assumes no heat or other losses, providing a rough estimate of power output. Understanding these equations is crucial for evaluating hydroelectric power efficiency.
Etak
Messages
5
Reaction score
0
Hi!

I need to know the equation/s that are used to deterimne how much power is generated through a hydroelectric power station in tems of the water flow.
It doesn't need to be that descriptive, just a basic explanation will be ok.

:smile:
 
Physics news on Phys.org
The power comes from the energy of the water moving through the power station. The water will have both Gravitational Potential energy (=m*g*h) and kinetic energy =(1/2mv^2).

You need to know what these values are before entering the power station, and on leaving the power station. The energy difference between the two sets of values gives you the energy transfer inside the power station.

Obviously this is assuming no heat losses, or other losses, but certainly gives you a 'ball-park' figure to work with.
 
Cool thanks.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top