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For a hydrogen atom in the ground state, what is the probability to find the electron between 1.00a and 1.01a, where a is the Bohr radius? It is not necessary to evaluate any integrals to solve this problem.

I know that P(r)=r^2*(R(r))^2. I used the R(r) expression for n=1, l=0 and then substituted values r=1a and r=1.01a

I subtracted P(1a)-P(1.01a) to get .0000537/a

Expressed as a percent, this is .0054/a

The answer in the back of the book is .0054

Why is my answer off by a factor of 1/a?

Any help would be appreciated!

Thanks

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# Hydrogen atom and probabilities

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