Hydrogen, Couloumbs and Quantum Mechanics

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SUMMARY

The discussion focuses on the perturbative analysis of the hydrogen atom's energy levels, specifically considering the finite size of the nucleus modeled as a uniformly charged spherical shell. It establishes that the electric field inside the shell is zero, leading to a constant potential within. The perturbation in the potential relative to the Coulomb potential is derived, and the shift in the ground-state energy is calculated using the ground-state wave function, yielding the expression ΔE₁ ≈ (e²/6πε₀)(δ²/a₀³) for the energy shift due to the nuclear charge distribution.

PREREQUISITES
  • Understanding of quantum mechanics, specifically the Schrödinger equation.
  • Familiarity with Gauss' law and electric fields.
  • Knowledge of perturbation theory in quantum mechanics.
  • Basic concepts of atomic structure, particularly the hydrogen atom.
NEXT STEPS
  • Study the application of perturbation theory in quantum mechanics.
  • Learn about the derivation of the Schrödinger equation for hydrogen-like atoms.
  • Explore the implications of finite nuclear size on atomic energy levels.
  • Investigate the mathematical techniques for evaluating integrals in quantum mechanics.
USEFUL FOR

Students of quantum mechanics, physicists studying atomic structure, and researchers interested in the effects of nuclear size on atomic energy levels.

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Homework Statement



In the derivation of the energy levels in the hydrogen atom one commonly assumes that the nucleus is a point charge. However, in reality the size of the nucleus is of the order of 1fm=10^−15m. Since this is very much smaller than the typical distance of the electron from the nucleus, which is of the order of a_0 \approx 0.5 Angstoms = 0.5 *10^{-10}m, the finite size of the nucleus can be taken into account perturbatively.

a)

Assume that the nucleus of the hydrogen atom is a uniformly charged spherical shell of radius \delta. According to Gauss’ law \int E \cdot dA = Q_{enclosed}/\epsilon_0, the electric field outside this shell is the same as for a point charge at the centre. However, from Gauss’ law also follows that the electric field
inside the shell is zero. Since the force -eE_r on the electron is given by the gradient -\partial V/\partial r of the potential, the potential must thus be constant inside the shell and indistinguishable from the Coulomb potential outside it.

Sketch the potential V (r), find the expression for it, and then find the perturbation \DeltaV relative to the Coulomb potential generated by a point-like nucleus.

b)

Use the ground-state wave function for a hydrogen atom with a point-like nucleus,

\Phi_{100}(r,\theta, \phi) = \frac{1}{\sqrt{\pi a_0^3}}e^{-r/a_0}

and calculate the shift of the ground-state energy due to the distribution of the nuclear charge overa finite spherical shell to first order in the perturbation.

c)
Expand the result of (b) in powers of \delta/a_0, retain only the first non-vanishing term, and thus show that the ground-state energy shift is approximately

\Delta E_1 \approx \frac{e^2}{6\pi\epsilon_0}\frac{\delta^2}{a_0^3}

Homework Equations



Given on sheet:

e^x = \Sigma \frac{x^n}{n!}

The Attempt at a Solution



Okay B, I think is a normal inverse square law graph, similar to that of gravity. It goes up with constant gradient until it reaches the radius R, then decreases inverse square law curve.

I am not sure however what to do for b). Do I need to insert the potential into a Schrödinger Equation?
 
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Okay, I have worked out that for b), I need to use the equation:

\Delta E = \int^{\infty}_{-\infty}\phi^*_n \Delta V(r) \phi_n

Now they give you phi, but I am slightly unsure as to how I get the Delta V(r). I thunk this bit is also part of a).

Any helpful suggestions of how to get this value?

Also, I think I have the graph wrong. I t should be more of a plateau, with the sides curving downwards, as attached.
 

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