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hi i need to know how can we find the gravitational force between two uniform rods of mass m and length l?
Healey01 said:I could be wrong in my way of thinking, but if one part of the bar is farther away than another, gravity will act differently and you cannot just use center of masses, right?
Two bars like this : | |
Will behave differently than : | --
And differently than: | /
But I'm sure its a function of their relative rotation, their lengths and the distance from their centers of mass.
I don't think so. Newton's law of gravity applies to point masses or special mass configurations (those with spherical symmetry). Of course, if the two rods are very far apart, you can approximate the answer by treating them as point masses with their mass concentrated at their centers. I presume that's not the case here.Astronuc said:The separation distance, r, is the distance between the centers of mass (CM), with mass m applied at CM. That is what the double integral would provide.
Use F=Gmm/r2
Ah, so that's supposed to be the relative orientation of the rods. (D'oh!) In that case, the integration is easier.Healey01 said:Though he did just say they were like this : ___ ___
Kurdt said:Cheers for the seconds Dick.
To calculate the gravitational force between two uniform rods, you can use the following formula: F = (G*m1*m2)/r^2, where G is the gravitational constant, m1 and m2 are the masses of the two rods, and r is the distance between their centers of mass. This will give you the force in Newtons.
The gravitational constant, denoted by G, is a fundamental constant in physics that represents the strength of the force of gravity. It is a universal constant and has a value of 6.674 x 10^-11 N*m^2/kg^2.
No, this method is specifically for calculating the gravitational force between two uniform rods. For non-uniform rods, you will need to use more complex equations that take into account the distribution of mass along the rods.
The gravitational force between two objects is inversely proportional to the square of the distance between their centers of mass. This means that the force will decrease as the distance between the rods increases.
This method is a simplified version and may not be accurate for all situations. It assumes that the rods are infinitely long, have uniform mass distribution, and are not affected by other external forces. In reality, these assumptions may not hold true, so it is important to use caution when using this method.