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## Homework Statement

What is the ratio of the rotational kinetic energy of the Earth to the rotational kinetic energy of the Moon as they spin about their axes?

## The Attempt at a Solution

Me = Mass of Earth (5.97 × 1024 kg)

Re = Radius of Earth (6.37 × 106 m)

Mm = Mass of Moon (7.35 × 1022 kg)

Rm= Radius of Moon (1.74 × 106 m)

this is all i know I don't know where to start. I know KE=(1/2)(moment of inertia)(angular velocity)