I need to transpose for the value of Q

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B=PRn-Q(Rn-1)/R-1

Mod note: This thread is closed. @Rodo, this appears to be homework that is misplaced, with no effort shown. You are welcome to repost in the Homework & Coursework section, but you need to use the homework template and show what you have tried.
 
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Rodo said:
B=PRn-Q(Rn-1)/R-1
Do you want to solve for Q or what?
 
Do you mean "solve for Q" (not "transpose")? The word "transpose" has quite a different meaning in Linear Algebra than it does in "ordinary algebra. And is that last -1 under the fraction sign? That is, Do you mean Q(Rn- 1)/(R- 1)?
And why is this in "Linear and Abstract Algebra"? Are these matrices? If so how are you defining that division by either R or R- 1?

If the letters just represent numbers (and so this should be in "General Math", not "Linear and Abstract Algebra"- of course, if you are just taking basic "algebra" you would not know what "Linear Algebra" and "Linear Algebra" are. It's a common mistake), then solve
B=PR^n-Q(R^n-1)/R-1 by
(1) Add 1 to both sides
(2) Add PR^n to both sides
(3) Multiply both sides by R
(4) Divide both sides by R^n- 1,
 
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Please make a question. Posting just a formula without explaining anything is like answering:
Q= AB + C
 

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