- #1

Dainy

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- 0

undefinedundefinedundefinedneed help=====)

(sin2x+sin4x)/(cos2x+cos4x)=tan3x

(sin2x+sin4x)/(cos2x+cos4x)=tan3x

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- Thread starter Dainy
- Start date

- #1

Dainy

- 2

- 0

undefinedundefinedundefinedneed help=====)

(sin2x+sin4x)/(cos2x+cos4x)=tan3x

(sin2x+sin4x)/(cos2x+cos4x)=tan3x

- #2

VietDao29

Homework Helper

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[tex]\cos \alpha + \cos \beta = 2 \cos \frac{\alpha + \beta}{2} \cos \frac{\alpha - \beta}{2}[/tex]

[tex]\cos \alpha - \cos \beta = - 2 \sin \frac{\alpha + \beta}{2} \sin \frac{\alpha - \beta}{2}[/tex]

[tex]\sin \alpha + \sin \beta = 2 \sin \frac{\alpha + \beta}{2} \cos \frac{\alpha - \beta}{2}[/tex]

[tex]\sin \alpha - \sin \beta = 2 \cos \frac{\alpha + \beta}{2} \sin \frac{\alpha - \beta}{2}[/tex]

Choose 2 of the above equations, and use them.

Can you go from there?

Viet Dao,

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