A 50.0 kg person dives from a cliff above the water. From what height must he dive if he experiences an average force equal to 5.0 times his body weight (W=mg), as he comes to a stop in the water? You may assume a stopping time of 0.400 s.(adsbygoogle = window.adsbygoogle || []).push({});

So first I solved for the average force:

average F= 5.0(mg) = 5.0(9.80m/s^2)(50.0kg) = 2450N

Next I used the equation m*delta v = average F*delta t to solve for delta v:

delta v = [(2450)(0.4)]/50.kg = 19.6 m/s

I was wondering if my above calculations are right and then I am not sure how to now find the height using the delta v!

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# Homework Help: I solved for the average force

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