I would appreciate some help with my geometry homework

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The discussion focuses on finding formulae for the transformation of a line defined by the equation a⋅x+b⋅y+c=0 under translation and rotation. For translation by a vector B=[u,v], the solution involves simply adding the vector to the coordinates. For rotation, the user is confused about whether to apply transformations directly or adjust for the specific point of rotation (x0,y0). It is suggested to first translate the line to the origin, apply the rotation formulas for the origin, and then translate back to the original point. This approach clarifies the transformations needed for both 90-degree and 180-degree rotations.
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2. A group of Japanese physicists works on a project where planar lines are in the form of solutions to equations
a⋅x+b⋅y+c=0
where a , b , and c are fixed reals satisfying a2+b2≠0 . They need to know formulae for the images of the line a⋅x+b⋅y+c=0 in the following cases:
1. Under the translation by a vector B=[u,v] ,
2. Under rotation about a point (x0,y0) by 180 degrees,
3. Under rotation about a point (x0,y0) by 90 degrees.
Please provide those formulae and a justification for them.

I know for number 1, you basically just add the vector B.
for 2 and 3 I do not know whether to use point slope form and just change the slope or if I need to change the coordinates to (-y,x) for 90 degree rotation and (-x,-y) for 180 degree rotation but those are for rotation about the origin and my problem does not state that. Does the slope for a 180 degree rotation go back to the same slope? I am really confused on which direction to take.
 
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Homework questions should be posted in the homework forum. ;)
 
Sorry! I'm new and I looked for that but couldn't find it!
 
carojay said:
I need to change the coordinates to (-y,x) for 90 degree rotation and (-x,-y) for 180 degree rotation but those are for rotation about the origin and my problem does not state that.

Why don't you use a combination of the things that you know. I think the point of the problem is that you know how to translate the line. Thus, you know how to move the point ##(x_0, y_0)## to ##(0,0)##. Next, you say that you know how to do rotation about the origin. You can apply that concept. Finally, you just have to translate ##(0,0)## back to ##(x_0, y_0)##.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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