Ideal gas law constant R conversion

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SUMMARY

The discussion focuses on converting the ideal gas law constant R from 8.31 (Pa * cu. meters) / (mol * Kelvin) to 10.73 (psia * cu. ft) / (lb. * mol * Rankine). Key conversion factors include 1 Pa = 1.4505E-7 psia, 1 cu. meter = 35.315 cu. ft, and 1 Rankine = 1.8 Kelvin. The confusion regarding the additional pounds in the denominator is clarified by the need to convert between gram-Moles and lb-Moles, using the conversion factor of 1 gram = 0.0022 lb. A recommended tool for automatic conversions is the PDAcalc program.

PREREQUISITES
  • Understanding of the ideal gas law (PV = nRT)
  • Familiarity with unit conversions in thermodynamics
  • Knowledge of mole conversions between gram-Mole and lb-Mole
  • Basic understanding of pressure and volume units
NEXT STEPS
  • Research the use of the PDAcalc program for unit conversions
  • Learn about the implications of using different mole units in gas law calculations
  • Explore the relationship between Kelvin and Rankine temperature scales
  • Study the derivation and application of the ideal gas law in various units
USEFUL FOR

Chemists, engineers, and students involved in thermodynamics or physical chemistry, particularly those working with gas laws and unit conversions.

sitinduk
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Hi, not sure if this is the right forum to ask this in, but I was trying to convert the ideal gas law constant R (from PV = nRT) from:

8.31 (Pa * cu. meters) / (mol * Kelvin) to the equivalent:

10.73 (psia * cu. ft) / (lb. * mol * Rankine)

Here's the conversion factors I've been using:
1 Pa = 1.4505E-7 psia (absolute pressure)
1 cu. meter = 35.315 cu. ft
1 Rankine = 1.8 Kelvin

What I don't understand is where does the extra pounds in the denominator of the 10.73 value come from? This is probably what's throwing off my calculations.

-Thanks
 
Science news on Phys.org
gm-Mole vs. lb-Mole

In the first equation "mole" means "gram-Mole"; in the second the unit is "lb-Mole". You need to convert between gm-Moles and lb-Moles.
 
Ahh, using 1 gram = 0.0022 lb I finally got it. Thanks a lot, this has really been bugging me :smile:
 
I always use this
R = 0.082 \frac{atm \cdot l}{mol \cdot K} = 2 \frac{cal}{mol \cdot K} = 8.314 \frac{J}{mol \cdot K}
 
sitinduk said:
Hi, not sure if this is the right forum to ask this in, but I was trying to convert the ideal gas law constant R (from PV = nRT) from:

8.31 (Pa * cu. meters) / (mol * Kelvin) to the equivalent:

10.73 (psia * cu. ft) / (lb. * mol * Rankine)

Here's the conversion factors I've been using:
1 Pa = 1.4505E-7 psia (absolute pressure)
1 cu. meter = 35.315 cu. ft
1 Rankine = 1.8 Kelvin

What I don't understand is where does the extra pounds in the denominator of the 10.73 value come from? This is probably what's throwing off my calculations.

-Thanks

Take a look at:
http://www.adacs.com/menu/PDAcalc_units.php This program runs on a palm, PocketPC,windows and will do all the conversions AUTOMATICALLY for you. Download the user manual which has an example of the PV = nRT formula that shows how it automatically convert between the different units.
 
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