1) Consider one-mole of gas in a heat engine undergoing the Otto Cycle
a) The gas absorbs heat, at constant volume between 120'C and 300'C
b) The gas expands adiabatically from V1 to V2 = 5V1
c) The gas cools, at constant volume to Td at point D where the pressure is 1At
d) The gas is then adiabatically compressed from V2 to V1 returning to the original temperature of 120'C
You may assume Cv = 5R/2 and Cp = 7R/2
What are the pressures and temperatures (in Kelvin) at points A,B,C,D?
Ideal gas law pV = nRT
Charle's law = V1/T1 = K and V1/T1 = V2/T2
Boyle's law = P1V1 = P2V2
The Attempt at a Solution
A = 120 + 273.15 = 393.15K
B = 300 + 273.15 = 573.15K
C = 1At
I'm guessing i'm going to have to use Boyle's and Charle's laws in order to fill in the blanks.
V1 / 573.15 = 5V1 / T2
T2 / 573.15 = 5V1 / V1
T2 / 573.15 = 4V1
But here's the problem, it doesn't appear like this is going to solve anything. I reach this barrier for the other blanks as well. Could someone possibly edge me in the right direction please?