Identical Hollow and Solid Spheres

AI Thread Summary
To determine which of two identical-looking spheres is hollow and which is solid, an experiment can be conducted by rolling both spheres down an incline. The solid sphere, having a smaller moment of inertia, will convert more gravitational potential energy into translational kinetic energy, resulting in a higher velocity at the bottom compared to the hollow sphere. The discussion emphasizes that the solid sphere will reach the base faster due to its lower resistance to rotation. It also clarifies that if both spheres were to roll at the same velocity, the one with the higher moment of inertia would possess greater rotational kinetic energy. Ultimately, the experiment hinges on observing the difference in velocities as they roll down the incline.
cassie123
Messages
15
Reaction score
0

Homework Statement



Two spheres look identical and have the same mass. However, one is hollow and the other is solid. Describe an experiment to determine which is which.

Homework Equations



mgh= ½ m v^2 + ½ I ω^2
where I= 2/3 mr2 for a hollow sphere
I=2/5 mr2 for a solid sphere

The Attempt at a Solution



You could allow the two spheres to roll an identical incline from rest. For both spheres, the gravitational potential energy will be transformed to both rotational kinetic energy and translational potential energy when they reach the base.

Since a solid sphere has a smaller moment of inertia, it is less resistant to rotation. More of the original gravitational potential energy will be converted into rotational potential energy for the solid sphere than for the hollow sphere. Thus, the hollow sphere must have more translational kinetic energy and will reach the bottom at a greater translational velocity than the solid sphere will.

Logically I believe that the solid sphere should go faster.. so I am not confident in my logic above.

Could you also argue that the at the moment released from rest the solid sphere will begin to rotate to fall down the incline before the hollow sphere due to the differences in inertia?
 
Physics news on Phys.org
cassie123 said:
Since a solid sphere has a smaller moment of inertia, it is less resistant to rotation. More of the original gravitational potential energy will be converted into rotational potential energy for the solid sphere than for the hollow sphere.
Think over this again.

If the solid sphere has a smaller moment of inertia, will its rotational energy be higher or lower than that of the hollow sphere, if they are rolling at the same rate?

Say sphere A will have a lower rotational energy than sphere B when rolling at the same rate, and both have the same mass. Given the same energy input to both, what can we then say about which one must be rolling faster?
 
andrewkirk said:
Think over this again.

If the solid sphere has a smaller moment of inertia, will its rotational energy be higher or lower than that of the hollow sphere, if they are rolling at the same rate?

Say sphere A will have a lower rotational energy than sphere B when rolling at the same rate, and both have the same mass. Given the same energy input to both, what can we then say about which one must be rolling faster?
Based on the equation for the conservation of energy: if a solid sphere has a smaller moment of inertia it will then have a lower rotational energy than a hollow sphere. So, the solid sphere must have a higher translational energy and reach the bottom at a higher velocity.
Better?
 
cassie123 said:
Based on the equation for the conservation of energy: if a solid sphere has a smaller moment of inertia it will then have a lower rotational energy than a hollow sphere. So, the solid sphere must have a higher translational energy and reach the bottom at a higher velocity.
Better?
If the spheres have the same velocity then the one with the higher moment of inertia will have the higher rotational kinetic energy, right?

But they do not have the same velocity. The proposed experiment only works if their velocities are different. Instead, something else is being held constant.
 
Last edited:
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top