If all the empty space of atoms were removed, how big would this earth be?

AI Thread Summary
If all the empty space in atoms were removed, the Earth would compress to approximately 500 meters in diameter, significantly larger than a marble but smaller than a large stadium. The discussion highlights the vast difference in size when comparing atomic scale to macroscopic objects. An iron atom's radius is about 1.2 x 10^-10 meters, while its nucleus is around 4.6 x 10^-15 meters, illustrating the immense scale factor involved. The concept of black hole density is also mentioned, noting that the black hole radius of Earth would be about 1 centimeter. Overall, the estimates vary widely, but the stadium size is closer to the actual compressed size of the Earth.
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Hi everyone, first time poster.
Considering some of the things discussed here, I apologize if my question sounds simplistic.

If this Earth could be compressed so that all the empty space in atoms would disappear how big would this Earth be?
My science teacher once told me that it would be the size of a marble, and I've also heard that it would be the size of a large stadium. I realize it's not an easy thing to estimate but that seems to be quite a difference.

An example of such scales of atoms would be appreciated. (i.e. I've also been told all 6.5 people in this world could be compressed into the size of a kidney bean)

Thanks!
 
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The stadium is closer. An iron atom has a radius of about 1.2 x 10-10 m and an iron nucleus about 4.6 x 10-15 m. So there is a factor of about 26000 in radius, which means the Earth would be about 500 m across.
 
The black hole radius of the Earth is about 1 cm.
 
Thanks for the answer! Come to think of it, I think my science teacher was referring to the black hole density, not the compressed atom density.
 
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