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## Homework Statement

8x^2-10xy+3y^2=26

**2. The attempt at a solution**

(8)(2x)-(-10x)y'+(y)(-10)+(3)(2y)y'=0

16x+10x(y')-10y+6y(y')=0

y'(10x+6y)+16x-10y=0

y'(10x+6y)=10y-16x

y'=(10y-16x)/(10x+6y)

y'=(5y-8x)/(5x+3y)

I know I'm doing something wrong but I can't see it for myself. Can someome point me into the right direction?