Magnification at a Different Distance from Mirror?

AI Thread Summary
The discussion revolves around calculating magnification when a person moves further from a mirror. Initially, a magnification of 1.50 is achieved at a distance of 12.0 cm, with a focal length of 0.36 m. When the person moves to a distance of 3.7 times the focal length, the magnification becomes -0.62, indicating an inverted image. The conversation highlights confusion regarding the signs of magnification for real and virtual images, noting that real images are typically inverted while virtual images are upright. Understanding these concepts is crucial for solving the problem accurately.
DaveMann
Messages
1
Reaction score
0

Homework Statement


The focal length between a person and his mirror that produces a magnification of 1.50 when his face is 12.0 cm away is 0.36 m. He then moves to a distance of 3.7 times the focal length away from her mirror. What is the magnification now?

Homework Equations


di/do=m
1/f=1/di+1/do

The Attempt at a Solution


I've been trying to work this out on paper for the last hour. When his distance is 2.6 times the focal length, the magnification is -0.62. I can't figure out why that is though. There seems to be 2 variables.
 
Physics news on Phys.org
The images can be real and virtual. One image is upside down, which one? What is the sign of magnification in case of a real image and in case of a virtual image?
 

Thread 'Rolling without slipping on a curved surface'

Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
View full post »
Thread 'Voltmeter readings for this circuit with switches'

Thread 'Voltmeter readings for this circuit with switches'

TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
View full post »
Thread 'Trying to understand the logic behind adding vectors with an angle between them'

Thread 'Trying to understand the logic behind adding vectors with an angle between them'

My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
View full post »

Similar threads

Find the location and length of the final image
Replies
2
Views
912
Concave mirror reflection, problems with drawing setup
Replies
5
Views
1K
Focal length of the eyepiece lens in a compound microscope
Replies
7
Views
1K
What Focal Length Eyepiece Provides a -125 Magnification?
Replies
1
Views
2K
I Understanding magnification of concave mirrors for near-eye situation?
Replies
11
Views
2K
Mirror placed horizontally between two half convex lenses
Replies
11
Views
1K
[LENS] Given focal length and height, find object distance
Replies
1
Views
3K
Calculating Image Height of Flower in Convex Mirror | Homework Question
Replies
3
Views
5K
Find Magnification of Reflecting Telescope
Replies
1
Views
2K
Optics - Adding magnification in an optical system
Replies
3
Views
2K

Hot Threads

Recent Insights

Back
Top