Improper integral concept help.

Click For Summary

Homework Help Overview

The discussion revolves around the evaluation of an improper integral, specifically the integral from -1 to 2 of dx/x^3. Participants are exploring the implications of divergence in the context of this integral.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • Participants are questioning the meaning of divergence in relation to the integral's evaluation. There is confusion about whether "diverges" implies a specific answer or simply indicates that the integral does not converge to a finite value.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the implications of divergence. Some have expressed frustration over the lack of a definitive answer and are looking for more helpful input regarding the evaluation process.

Contextual Notes

Participants are grappling with the concept of improper integrals and the conditions under which they diverge. There is a noted emphasis on the need for clarity in understanding the evaluation of such integrals.

frasifrasi
Messages
276
Reaction score
0
Ok, my book has the example int from -1 to 2 of dx/x^3

this gets split into int from -1 to 0 of dx/x^3 and int from 0 to 2 of dx/x^3.

Now, he had previously determined that the second integral returned positive infinity (diverges) by taking the lim as b approaches 0+.


So, the book goes on to say that since the second integral diverges the original integral also diverges.

--> but what does that mean? is "divergers" the answer to "evaluate the int from -1 to 2 of dx/x^3" ? Or does it mean the the answer is just infinity?

Can anyone explain?
 
Physics news on Phys.org
It means that it diverges.
 
so what is the answer ? what does this mean ?? what should I conclude from this? does it mean that I shoudl stope evaluating the original improper integral?

I would appreciate HELPFUL input. If you aren't going to clarify the solution, please igonre the thread.
 
frasifrasi said:
so what is the answer ?
There is none.
what does this mean ?? what should I conclude from this?
That the expression is meaningless.
does it mean that I shoudl stope evaluating the original improper integral?
Quite so.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
3
Views
2K
  • · Replies 105 ·
4
Replies
105
Views
11K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K