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Improper integral concept help.

  1. Oct 6, 2007 #1
    Ok, my book has the example int from -1 to 2 of dx/x^3

    this gets split into int from -1 to 0 of dx/x^3 and int from 0 to 2 of dx/x^3.

    Now, he had previously determined that the second integral returned positive infinity (diverges) by taking the lim as b approaches 0+.


    So, the book goes on to say that since the second integral diverges the original integral also diverges.

    --> but what does that mean? is "divergers" the answer to "evaluate the int from -1 to 2 of dx/x^3" ? Or does it mean the the answer is just infinity?

    Can anyone explain?
     
  2. jcsd
  3. Oct 6, 2007 #2

    arildno

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    It means that it diverges.
     
  4. Oct 6, 2007 #3
    so what is the answer ??? what does this mean ?? what should I conclude from this? does it mean that I shoudl stope evaluating the original improper integral???

    I would appreciate HELPFUL input. If you aren't going to clarify the solution, please igonre the thread.
     
  5. Oct 6, 2007 #4

    arildno

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    There is none.
    That the expression is meaningless.
    Quite so.
     
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