In the following figure, the space b/w the glass lenses is filled with

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SUMMARY

The discussion focuses on calculating the focal length of a lens system filled with water between glass lenses using the lens maker's formula. The formula is expressed as 1/f = (μ-1)(1/R1 - 1/R2), where μ represents the refractive index. A key point raised is the correct substitution of the refractive index of glass relative to water, which is validated through the basic refraction equation. The conversation emphasizes the importance of understanding the refractive indices involved in lens calculations.

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In the following figure, the space b/w the glass lenses is filled with water. We have to find the focal length of the system (radii of curvature, refractive indices given)

[URL]http://203.196.176.41/VLEBT_RootRepository/Resources/6c32207c-7c5a-4462-b90c-89b0c196bc72.gif[/URL]

Now to calculate the focal length of the system of lenses, we have to calculate the focal length of each lens. To find the same for water lens, we use lens maker's formula-
1/f = (μ-1)(1/R1 - 1/R2)
Why don't we substitute μ as gμw instead of aμw as given in all books? Doesn't the light travel from glass to water?
 
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if i understood your question rite, it is 100 % correct to use refractive index of glass wrt water in this sum...
 


can you show me a source for that claim?
 


Use the basic formula for refraction at a curved single interface twice,factoring in the assumption of thin lenses.You will see that terms cancel out and the final equation will agree with what you are saying.The 1 in the lens maker's formula you brandished is because the refractive index of air is very close to 1.If I remember correctly the basic equation of which the lensmaker's formula is a special case is:

n1/u + n3/v = n2-n1/R1 + n3-n2/R2
Where n1,n2,n3 are refractive indices of medium to the left,the lens and the medium to the right respectively.
 

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