- #1
NikkiNik
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Homework Statement
If the apex angle of a prism is f = 74.3° (see figure below),
http://i32.photobucket.com/albums/d2/NikkiNik88/apex.gif
what is the minimum incident angle for a ray if it is to emerge from the opposite side (i.e., not be totally internally reflected), given n = 1.55?
Homework Equations
sin(alpha + delta)/2 =nsin(alpha/2)
delta = incindence angle + alpha/2
The Attempt at a Solution
delta = min angle of deviation
alpha = apex angle
I solved for delta and got 65.4 deg
Then I used the second equation to solve for the incident angle and got 28.3 deg
I'm not even sure if I should go so far as to solve for delta. I'm thinking there is a simpler way