- #1
mkkeyan
- 10
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I have a question on pure translation of inclined bar. The problem statement is:
A homogenous slender bar with a mass of 4 kg and a length of 500mm being pushed along the smooth horizontal surface by a horizontal force P=60N. Determine the angle θ for translation. What is the accompanying acceleration? (FBD and kinetic diagram attached)
I used the following equations:
⅀Fx=max
⅀Fy=0
⅀MG=0 (since rod is in translation)
The results
θ = 33.4°
a = 15m/s2
My question is, there exists a moment about point A equal to 8.26Nm. What is the physical meaning of this moment? Would not the rod rotate about A due to this moment? Requesting for help please.
A homogenous slender bar with a mass of 4 kg and a length of 500mm being pushed along the smooth horizontal surface by a horizontal force P=60N. Determine the angle θ for translation. What is the accompanying acceleration? (FBD and kinetic diagram attached)
I used the following equations:
⅀Fx=max
⅀Fy=0
⅀MG=0 (since rod is in translation)
The results
θ = 33.4°
a = 15m/s2
My question is, there exists a moment about point A equal to 8.26Nm. What is the physical meaning of this moment? Would not the rod rotate about A due to this moment? Requesting for help please.