Inclined plane + Inclined force. Normal reaction force = ?

AI Thread Summary
The discussion revolves around calculating the normal reaction force and tension for an object on a 30-degree inclined plane with a weight of 20N. The user has determined the tension to be (20/3)*sqrt3 Newtons by resolving horizontal forces. To find the normal reaction force, it is suggested to set the sum of vertical components equal to zero, incorporating the weight force into the equation. The user is confused about the weight force and how it fits into the equilibrium conditions. The conversation emphasizes the importance of resolving forces correctly to achieve accurate results.
1337pHysiX
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ok I'm desperate now lol n this is my first time on PF.

I've just had an exam and I'm sure i got this question wrong. But i'd like to know:

the normal reaction force and the tension/Force F.

The question is: There is this object that has a weight of 20N. It is on an inclined plane that is 30 degrees and it is held by a force 30 degrees to the plane. Determine the normal reaction force and the tension in the string.

Please give me as much relevant working as possible. Thank you for your help!

I have attached the diagram/question.
 

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Show us what you've done and where you got stuck.

Hint: What are the conditions for equilibrium?
 
ok.

Resolving forces, I've figured that the tension/Force F = (20/3)*sqrt3 Newtons

now...i'm not sure wat the normal reaction force is. My friends are telling me that it's Normal Reaction + Tension - Weight Force = 0...but wat's the weight force then. lol

The only logic that i can conclude from this is that:
Normal Reaction force + all vertical components above plane = sum of all vertical components under plane, which kinda makes sense to me n is getting me the right answers right now.

well looking forward to ur reply =]
 
1337pHysiX said:
Resolving forces, I've figured that the tension/Force F = (20/3)*sqrt3 Newtons
Good! The way you solved for this was to add up all horizontal force components (parallel to the plane) and set them equal to zero. Do the same for vertical force components (perpendicular to the plane) to find the normal force.

now...i'm not sure wat the normal reaction force is. My friends are telling me that it's Normal Reaction + Tension - Weight Force = 0...but wat's the weight force then. lol
That's true, but you need to use the vertical components of those forces.

The only logic that i can conclude from this is that:
Normal Reaction force + all vertical components above plane = sum of all vertical components under plane, which kinda makes sense to me n is getting me the right answers right now.
Sounds good to me.
 

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