Inclined Planes - Multiple Ones

AI Thread Summary
The discussion revolves around calculating the forces and final velocities of a freight car moving down multiple inclined planes at different angles, specifically 60 degrees and 45 degrees. The user seeks guidance on how to determine these values, particularly when the car transitions between planes and potentially bounces. Key points include the suggestion to apply the conservation of energy for frictionless slopes and the work-energy theorem for inclined planes with friction. Additionally, the coefficient of restitution is mentioned as necessary for calculating bounces at sharp transitions. Understanding these principles is essential for accurately modeling the car's motion in this setup.
drizzt56
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This isn't exactly a specific question, but it is part of my homework (project). Anyways, suppose I have an inclined plane at 60 degrees. I can measure the mass of a freight car on top of the plane to calculate the force and final velocity of that car... I did this before in physics, and it filled up half a page of math so I won't elaborate too much. The problem is then what happens to these values when the car rolls on another inclined plane connected to the first at a less steep angle, like 45 degrees? What would happen to its final velocity if after it hits this less steep inclined plane, it hits an inclined plane in the opposite direction? The setup would look something like V, except each side isn't one uniform plane, but two that's inclined at different angles. Can someone show me how to calculate the force, final velocity, etc of the car? For example purposes, assume the car is 1kg and just make up heights for the inclined planes.
 
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welcome to pf!

hi drizzt56! welcome to pf! :wink:

it'll just get stuck at the bottom of the V, won't it? :confused:

but if it does somehow manage to carry on, just use conservation of energy if the slopes are frictionless, and the work-energy theorem if they aren't :smile:

(and you'll need a coefficient of restitution if the bottom of the V is sharp, so that it "bounces")
 
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