Increase Entropy: Solve 0.15kg Ball Dropped from 24m Tower

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The discussion focuses on calculating the increase in entropy resulting from a 0.15 kg baseball dropped from a 24 m tower at 19 °C. The relevant equation for entropy change is ΔS = Q/T, where Q represents the heat transfer and T is the temperature in Kelvin. Participants express confusion about the energy calculations involved and seek guidance on how to approach the problem without their notes. Clarification is provided that the object in question is a baseball, not a basketball. The thread emphasizes the need for understanding energy transformation and entropy in this context.
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Homework Statement



On a day when the air temperature is 19 °C, a 0.15 kg baseball is dropped from the top of a 24 m tower. After the ball hits the ground, bounces a few times, and comes to rest, by how much has the entropy of the universe increased?

Homework Equations



ΔS = Q/T

Also gravity is 6.7 x 10^ -11 m^3/(kg x s^2)

The Attempt at a Solution



I know that my answer should come out in units of J/K but I cannot remember how to work this problem and lost all of my notes. Please any help in getting me started would be greatly appreciated.
 
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How much energy does the basket ball have?
 
I like Serena said:
How much energy does the basket ball have?

There is no basketball, it's a baseball.
 

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