Increment value of equvalent resistance when the resistances are parallel

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The discussion focuses on calculating the increment in equivalent resistance (d(R3)) for two resistors (R1 and R2) in parallel. The equivalent resistance is defined as R3 = R1*R2/(R1+R2). The total differential of R3 is expressed as dR3 = (∂R3/∂R1)dR1 + (∂R3/∂R2)dR2. Participants explore the relationship d(R3)/R3 = d(R1)/R1 + d(R2)/R2 + d(R1+R2)/(R1+R2) and seek clarification on its derivation. The conversation emphasizes understanding the mathematical functions involved in resistance calculations.
sudhir1962
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R1 & R2 are two resistances in parallel. d(R1) & d(R2) are the incremnet in resistance. If R3 is the equvalent resisitance such that R3=R1*R2/R1+R2, then if d(R3) is increment in equvalent resistance. What is the value of d(R3)/R3.
 
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Hmm, well, if this is anything like I'm seeing it to be, you're dealing with functions:
R_3:\mathbb{R}^2\to\mathbb{R}
So the total differential/change of R_3 would be:
dR_3=\frac{\partial R_3}{\partial R_1} dR_1 + \frac{\partial R_3}{\partial R_2} dR_2
 
Actually I found it in some place as follows

d(R3)/R3= d(R1)/R1+d(R2)/R2+d(R1+R2)/(R1+R2), please let me know how it is arrived.
 
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