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## Homework Statement

[itex]\int_1^\infty \! \frac{(sin(x)+5)}{x^3} \, dx[/itex]

"Find two simpler integrals, one larger and one smaller."

## Homework Equations

## The Attempt at a Solution

How could I make this a simpler (ie, solvable) integral? It's been straight forward with other integrals like this:

[itex]\int_1^\infty \! \frac{1}{\sqrt{x^4+10}} \, dx \rightarrow \int_1^\infty \! \frac{1}{\sqrt{x^4}} \, dx[/itex]

Doing this would give an overestimate since the denominator is smaller. But how would I do it for the integral in question?