Indefinite Integration Problem

opticaltempest
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Calc I - Simple Indefinite Integration Problem

Hello,

Here is an indefinite integration problem I have been
working on. Would anyone be willing to check my solution?
Are my assumptions about replacing the C and -C correct?

http://img457.imageshack.us/img457/8933/problem0kw.jpg"

http://img457.imageshack.us/img457/2315/solution9zq.jpg"

Thanks
 
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Set up your integrals as definite integrals and the constants will take care of themselves! :)
 
This is my first section on covering integrals so I haven't covered definite integrals yet.
 
It would make more sense to combine the two constants (and would be much better to use different letters to represent them) into one, then determine its value.
 
I got some more help on this problem today but I am still stuck. It was suggested to
me that after realizing v(0)=v_0 we can come up with

v_0^2 = 2GM(1/R) + C

How can we conclude this?
Why replace the 1/y with 1/R ?Here is the entire solution that was presented to me
--------------------------------------------------

v^2 = 2GM(1/y) + C

then from v(0)=v_0 we would have obtained

[v_0]^2 = 2GM(1/R) + C

C = [v_0]^2 - 2GM(1/R)

so that

v^2 = 2GM(1/y) + [v_0]^2 - 2GM(1/R)

which can be rewritten as

v^2 = [v_0]^2 + 2GM( 1/y - 1/R)
http://img440.imageshack.us/img440/6539/solution14yb.jpg"

http://img440.imageshack.us/img440/5108/solution20jn.jpg"

Thanks
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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