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Indefinite Integration Problem

  1. Oct 22, 2005 #1
    Calc I - Simple Indefinite Integration Problem


    Here is an indefinite integration problem I have been
    working on. Would anyone be willing to check my solution?
    Are my assumptions about replacing the C and -C correct?

    http://img457.imageshack.us/img457/8933/problem0kw.jpg" [Broken]

    http://img457.imageshack.us/img457/2315/solution9zq.jpg" [Broken]

    Last edited by a moderator: May 2, 2017
  2. jcsd
  3. Oct 22, 2005 #2


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    Science Advisor
    Homework Helper

    Set up your integrals as definite integrals and the constants will take care of themselves! :)
  4. Oct 23, 2005 #3
    This is my first section on covering integrals so I haven't covered definite integrals yet.
  5. Oct 23, 2005 #4


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    Science Advisor

    It would make more sense to combine the two constants (and would be much better to use different letters to represent them) into one, then determine its value.
  6. Oct 25, 2005 #5
    I got some more help on this problem today but I am still stuck. It was suggested to
    me that after realizing v(0)=v_0 we can come up with

    v_0^2 = 2GM(1/R) + C

    How can we conclude this?
    Why replace the 1/y with 1/R ?

    Here is the entire solution that was presented to me

    v^2 = 2GM(1/y) + C

    then from v(0)=v_0 we would have obtained

    [v_0]^2 = 2GM(1/R) + C

    C = [v_0]^2 - 2GM(1/R)

    so that

    v^2 = 2GM(1/y) + [v_0]^2 - 2GM(1/R)

    which can be rewritten as

    v^2 = [v_0]^2 + 2GM( 1/y - 1/R)

    http://img440.imageshack.us/img440/6539/solution14yb.jpg" [Broken]

    http://img440.imageshack.us/img440/5108/solution20jn.jpg" [Broken]

    Last edited by a moderator: May 2, 2017
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