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In mutual induction, how can we increase the induced current, not e.m.f.?
Increasing Induced Current in Mutual Induction
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To increase the induced current in mutual induction without raising the electromotive force (EMF), lowering the resistance of the conductor is suggested, as per Ohm's Law (V=IR). Reducing the number of turns in the coupled circuit can also lead to a higher current since a decrease in EMF results in an increase in current. Additionally, increasing the number of coils in a solenoid or toroid can enhance the magnetic field interaction, potentially boosting the induced current. The discussion emphasizes the balance between EMF and current in the context of mutual induction. Overall, various methods can be employed to manipulate induced current effectively.
Neglect gravity other than that of water; neglect friction.
F1=ρgsh=1000*10*1*(1+4)=50000 N;
F1=ρgsh=1000*10*0.1*4=4000 N;
F3=50000-4000=46000 N?
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook.
Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water.
I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it.
I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction.
I'm not able to figure out, why my solution is wrong, if it is wrong .
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