Induced emf in a square loop at rest

AI Thread Summary
To determine the induced emf in a square loop at rest near a straight wire carrying a time-varying current, the relevant equation is emf = (μIva²)/(2π(a+b)b). The current I(t) is given as I(t) = (15.0 A)sin(2500t), with distances a = 12.0 cm and b = 15.0 cm. The user initially attempted to substitute I into the emf equation but found it unhelpful, indicating a lack of clarity on the application of Faraday's law in this context. The discussion emphasizes that both Ampere's law and Faraday's law are crucial for solving the problem. Further assistance is sought to clarify the correct approach to this physics problem.
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Homework Statement



Determine the emf induced in the square loop in the figure if the loop stays at rest and the current in the straight wire is given by I(t) = (15.0 A)sin(2500t) where t is in seconds. The distance a is 12.0 cm, and b is 15.0 cm.

Homework Equations



In the question prior to this one in the homework, emf=(uIv(a^2))/(2pi(a+b)b)



The Attempt at a Solution



I initially attempted to just substitute the equation for I into the emf equation but that hasn't worked. I'm clueless on how to proceed.

Please help! Thank you!
 

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This is not just an Ampere's law problem. Faraday's law also applies.

AM
 

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